2Pacのインスタグラム(2pac) - 6月17日 00時23分
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌??❌❌?????????????❌❌????❌❌❌????❌❌??❌❌❌❌???❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
mark.rowe.illuminati.blogger.z
james johnson|illuminati definition|blogs|Google+ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ ❌❌❌❌❌❌❌❌🚫🚫❌❌🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫🚫❌❌🚫🚫🚫🚫❌❌❌🚫🚫🚫🚫❌❌🚫🚫❌❌❌❌🚫🚫🚫❌❌❌❌❌❌❌ Given that matrix A is a 3x3 matrix. Diagonalize A.
det(A - lamda(I)) = 0, [(A - lamda(I)](x) = 0, v1 = (x,y,z), v2 = (x,y,z), v3 = (x,y,z), P = [v1 v2 v3], D = P^(-1)(A)(P) diagonalized matrix A (only if P is invertible) is matrix D. However, A = [v1,v2,v3], where v1 = (-1,-3,-3), v2 = (4,4,1), v3 = (-2,0,3) with eigenvaules 1,2,3, but obviously D = P^(-1)AP. Matrix P computed is P = [v1,v2,v3], where v1 = (1,3,4), v2 = (2,3,3), v3 = (1,1,1), and matrix D = [v1,v2,v3], where v1 = (3,0,0), v2 = (0,2,0), v3 = (0,0,1). "Whistleblown project Blue Beam," when truth and liberty overpowered corruption and lies is now. Blog that!
#MarkRoweBlog
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